Shell script command line supports passing arguments(also called parameters) like any other scripting Language. Command-line arguments consist of one or more words, which are separated by balls blanks or TABS. In this blog post, we will see how arguments can be passed to scripts while calling and can be accessed within the script.
Syntax and Example
The basic syntax for passing the arguments is given below.
bash bashLimArguments.sh arg1 args1 argsn
Let’s take the below example where we will pass two arguments to the Shell script.
#!/bin/bash
# We will read 2 arguments from the command Line #
echo "Script Name " $0
echo "First Argument " $1
echo "First Argument " $2
echo "Printing All Arguments At Once "
echo "$*"
Let’s run the above script in the Shell.
%bash bashLimArguments.sh 1 2
Script Name bashLimArguments.sh
First Argument 1
First Argument 2
Printing All Arguments At Once
1 2
Script Parameters
We have the below options available when using command-line arguments with Shell script.
| Parameters | Description |
$0 | Name of the script which ran |
$1 to $n | $1is the first argument, $2 is the second argument till $n nth arguments. We need to enclose arguments using braces after the 10th argument like ${10},${11} and so on |
"$*" | Values of all the arguments. All arguments need to be double-quoted |
$# | Total number of arguments passed to script |
$? | Exit status id of the last command executed. |
$! | Process id of the last command |
